2024 IGCSE Additional Mathematics May/June 0606/12 Q9

2024 IGCSE Additional Mathematics May/June 0606/12 Q9

10 marks

In this question, all distances are in metres and time, \(t\), is in seconds.

A particle \(P\) moves with a speed of \(14.5\) parallel to the vector \(\begin{pmatrix}-20\\21\end{pmatrix}\).

  1. Find the velocity vector of \(P\).[2]

Initially, \(P\) has position vector \(\begin{pmatrix}3\\5\end{pmatrix}\).

  1. Write down the position vector of \(P\) at time \(t\).[2]

A second particle \(Q\) has position vector \(\begin{pmatrix}-1\\3\end{pmatrix}+\begin{pmatrix}-5\\7.5\end{pmatrix}t\) at time \(t\).

  1. Find, in terms of \(t\), the distance between \(P\) and \(Q\) at time \(t\). Simplify your answer.[4]
  2. Hence show that \(P\) and \(Q\) never collide.[2]

Solution:

Solution locked

Sign in to view the step-by-step solution

Similar questions are unavailable for this question.
Answer:(a) \(\begin{pmatrix}-10\\10.5\end{pmatrix}\,\mathrm{m\,s}^{-1}\), in the given vector's direction. (b) \(\begin{pmatrix}3-10t\\5+10.5t\end{pmatrix}\). (c) \(\sqrt{34t^2-28t+20}\,\mathrm{m}\). (d) Discriminant \(-1936<0\); no collision.

Need help? Join our JC Math tuition classes.

Learn more