2024 IGCSE Additional Mathematics May/June 0606/11 Q2

2024 IGCSE Additional Mathematics May/June 0606/11 Q2

6 marks

DO NOT USE A CALCULATOR IN THIS QUESTION.

The polynomial \(\mathrm{p}\) is such that \(\mathrm{p}(x)=6x^3-35x^2+34x+45\).

  1. Find \(\mathrm{p}(x)\) in the form \((2x-5)\mathrm{q}(x)+r\), where \(\mathrm{q}(x)\) is a polynomial and \(r\) is a constant.[3]
  2. Hence write the expression \(\mathrm{p}(x)-5\) as a product of linear factors.[2]
  3. Hence write down the solutions of the equation \(\mathrm{p}(x)=5\).[1]

Solution:

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Answer:(a) \(\mathrm{q}(x)=3x^2-10x-8,\ r=5\). (b) \((2x-5)(3x+2)(x-4)\). (c) \(x=\dfrac52,-\dfrac23,4\).

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