2024 IGCSE Additional Mathematics February/March 0606/12 Q6

2024 IGCSE Additional Mathematics February/March 0606/12 Q6

9 marks

In this question all distances are in metres and all times are in seconds.

    1. The diagram shows the velocity–time (\(v\)–\(t\)) graph of a particle travelling in a straight line. The particle travels a distance of \(2750\,\mathrm{m}\) in \(120\,\mathrm{s}\). Find the velocity, \(V\), of the particle when \(t=70\).[2]
    2. Find the acceleration of the particle for \(70<t<120\).[2]
  1. A different particle moves in a straight line such that its velocity, \(v\,\mathrm{m\,s}^{-1}\), \(t\) seconds after leaving a fixed point \(O\), is given by \(v=t(t^2+5)^{\frac12}\).
    1. Find the exact acceleration of the particle when \(t=2\).[4]
    2. Explain why the particle does not change direction for \(t>0\).[1]

Solution:

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Answer:(a)(i) \(V=50\,\mathrm{m\,s}^{-1}\) (ii) \(-1\,\mathrm{m\,s}^{-2}\) (b)(i) \(\dfrac{13}{3}\,\mathrm{m\,s}^{-2}\) (ii) \(v>0\) for \(t>0\).

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