2024 IGCSE Additional Mathematics February/March 0606/12 Q5

2024 IGCSE Additional Mathematics February/March 0606/12 Q5

13 marks

The polynomial \(\mathrm{p}\) is such that \(\mathrm{p}(x)=5x^3+ax^2+39x+b\), where \(a\) and \(b\) are constants.

  1. Given that \(x+3\) is a factor of both \(\mathrm{p}(x)\) and \(\mathrm{p}'(x)\), find the values of \(a\) and \(b\).[5]
  2. Hence solve the equation \(\mathrm{p}(x)=0\).
    You must show your working.[3]
  3. Hence, using your values for \(a\) and \(b\), solve the equation
    \(5\mathrm{cosec}^3 2\theta+a\mathrm{cosec}^2 2\theta+39\mathrm{cosec}\,2\theta+b=0\quad\text{for}\quad0^\circ\leq\theta\leq360^\circ\).[5]

Solution:

Solution locked

Sign in to view the step-by-step solution

Similar questions are unavailable for this question.
Answer:(a) \(a=29,\ b=-9\) (b) \(x=-3\) or \(x=\dfrac15\) (c) \(\theta=99.7^\circ,170.3^\circ,279.7^\circ,350.3^\circ\)

Need help? Join our JC Math tuition classes.

Learn more