The gradient function of a curve $y = f(x)$ is given by $\frac{36}{(2x + 1)^2}$ for \(x &gt

Question

The gradient function of a curve $y = f(x)$ is given by $\frac{36}{(2x + 1)^2}$ for $x > -\frac{1}{2}$. The curve passes through the point $\left(\frac{1}{2}, 2\right)$. Find the equation of the curve.[3] Find the angle, in degrees, that the tangent to the curve at $x = 1$ makes with the $x$-axis.[2]

Accepted Answer

(a) $y = -\frac{18}{(2x + 1)} + 11$ (b) $\theta = 76.0^{\circ} $

2024 GESS PRELIMS P1 Q6

2024 GESS PRELIMS P1 Q6