The diagram shows part of the graph of $y = a \tan bx + c$. The graph has vertical asymptotes at \

Question

The diagram shows part of the graph of $y = a \tan bx + c$. The graph has vertical asymptotes at $x = -4\pi$ and $x = 4\pi$ and passes through the points $P$ and $Q$. Explain why $b = \frac{1}{8}$.[2] Hence find the equation of the curve.[2] The function $\mathrm{f}(x)$ is defined by $\mathrm{f}(x) = 4 + 3 \sin 2x$ for $0^\circ \le x \le 360^\circ$. Sketch the graph of $y = \mathrm{f}(x)$ on the axes below.[2]

Accepted Answer

(a)(i) $b = \frac{1}{8}$ (a)(ii) $y = 4\tan{ \left(\frac{x}{8}\right) } + 3$

2024 FMSS PRELIMS P1 Q4

2024 FMSS PRELIMS P1 Q4