2024 EJC Promo Q6

2024 EJC Promo Q6

8 marks
  1. Write down the derivative of \({{\sin }^{n}}\theta \) with respect to \(\theta \), where \(n\) is a constant and \(n\ge 1\). [1]
  2. Using the substitution \(x=2{{\cos }^{2}}\theta \) for \(0\le \theta \le \frac{\pi }{2}\), show that
    \(\displaystyle\int{x}\sqrt{1-\frac{x}{2}}\ \mathrm{d}x=8\displaystyle\int{\left( \cos \theta {{\sin }^{4}}\theta -\cos \theta {{\sin }^{2}}\theta \right)}\ \mathrm{d}\theta \). [4]
  3. Hence find \(\displaystyle\int{x}\sqrt{1-\frac{x}{2}}\ \mathrm{d}x\). [3]

Solution:

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Answer:(a) \(n\sin^{n-1}\theta\cos\theta\). (b) Shown. (c) \(\frac85(1-\frac x2)^{\frac52}-\frac83(1-\frac x2)^{\frac32}+C\).

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