It is given that for two events \(A\) and \(B\),
\[\mathrm{P}(A) = 0.35, \mathrm{P}(B) = x \text{ and}\hspace{0.5em} \mathrm{P}(A' \cap B') = 0.25.\]
The event \(C\) is such that \(\mathrm{P}(A | C) = 0.35\).
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