By expressing \(\frac{3x-7}{\left( x+3 \right)\left( x-2 \right)}-1\) as a single simplified fraction, solve exactly the inequality \(\frac{3x-7}{\left( x+3 \right)\left( x-2 \right)}<1\).[3]
Hence, solve exactly the inequality \(\frac{3{{\mathrm{e}}^{x}}-7}{\left( {{\mathrm{e}}^{x}}+3 \right)\left( {{\mathrm{e}}^{x}}-2 \right)}<1\).[2]
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