2024 CJC P2 Q2

2024 CJC P2 Q2

11 marks
Prelims

The functions \(\mathrm{f}\) and \(\mathrm{g}\) are defined by

\(\mathrm{f}:x\mapsto \frac{3-2x}{x+2}\), for \(x\in \mathbb{R}\), \(x>-2\),

\(\mathrm{g}:x\mapsto \left| x \right|-1\), for \(x\in \mathbb{R}\).

  1. Find \({{\mathrm{f}}^{-1}}\left( x \right)\) and state its domain.[3]
  2. Hence find \({{\mathrm{f}}^{2024}}\left( 1 \right)\).[1]
  3. Show that \(\mathrm{fg}\) exists and find its range.[3]
  4. Solve \(\mathrm{f}\left( x \right)>\mathrm{g}\left( x \right)\), giving your answer in exact form.[4]

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Answer:(a) \(f^{-1}(x)=\frac{3-2x}{x+2}\), with domain \((-2,\infty)\) (b) \(f^{2024}(1)=1\) (c) \(fg\) exists, and \(\operatorname{range}(fg)=(-2,5]\) (d) \(-2<x<\frac{\sqrt{29}-3}{2}\)

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