Events $A$ and $B$ are such that $\mathrm{P}(B) = 0.25$, $\mathrm{P}(B \cap A') = 0.15$

Question

Events $A$ and $B$ are such that $\mathrm{P}(B) = 0.25$, $\mathrm{P}(B \cap A') = 0.15$ and $\mathrm{P}(A \cap B') = p$. Find $\mathrm{P}(A)$ in terms of $p$.[3] If events $A$ and $B$ are independent, calculate the value of $p$.[2] Find $\mathrm{P}(A \cap B | B)$.[2]

Accepted Answer

(a)p+0.1 (b)p=0.3 (c)required probability = 0.4

2024 CJC H1 Q8

2024 CJC H1 Q8