2024 CGSS P1 Q10

2024 CGSS P1 Q10

11 marks

The diagram shows a running track \(ABCD\). \(D\) is a point on the straight line \(EC\). It is given that \(AB = 280\text{ m}\), \(AD = 150\text{ m}\), \(\text{angle}\hspace{0.5em} BCD = \text{angle}\hspace{0.5em} DAB = 90^\circ\) and \(\text{angle}\hspace{0.5em} ADE = \theta\), where \(0^\circ < \theta < 90^\circ\).

  1. Show that \(L\text{ m}\), the length of the running track, is given by
    \(L = p + 130\cos\theta + 430\sin\theta\), where \(p\) is a constant.[3]
  2. Express \(L\) in the form \(p + R\cos(\theta - \alpha)\), where \(R > 0\) and \(\alpha\) is an acute angle.[3]
  3. Xin Ting ran five complete laps around the track.
    She claims that she ran a total of \(5\text{ km}\). Explain why she might be wrong.[2]
  4. Given that the running track is \(700\text{ m}\) long, find the value of \(\theta\).[3]

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Answer:(a) \(p=430\). (b) \(R=10\sqrt{2018}\), \(\alpha\approx73.2^\circ\). (c) Five laps are at most \(4396.11\) m, less than \(5\) km. (d) Formal acute root \(20.1^\circ\), rejected because \(CD<0\); no valid pictured \(700\) m track.

Need help? Join our A-Maths tuition classes.

Learn more