
The diagram shows a running track \(ABCD\). \(D\) is a point on the straight line \(EC\). It is given that \(AB = 280\text{ m}\), \(AD = 150\text{ m}\), \(\text{angle}\hspace{0.5em} BCD = \text{angle}\hspace{0.5em} DAB = 90^\circ\) and \(\text{angle}\hspace{0.5em} ADE = \theta\), where \(0^\circ < \theta < 90^\circ\).
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