\(P\), \(Q\) and \(R\) are points on level ground. \(QR=35\text{ m}\), \(PR=55\text{ m}\) and angle \(QPR=27^\circ\text{ m}\).
Calculate angle \(PQR\).
Answer: Angle \(PQR=\ldots\ldots\ldots\)[2]
In triangle \(XYZ\), \(XY=(5x-1)\text{ cm}\), \(XZ=(2x-3)\text{ cm}\) and \(YZ=(x+1)\text{ cm}\).
Explain why the triangle above is not right angled. Show your working clearly.[3]
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Answer:(a) \(45.5^\circ\), using the acute angle shown. (b) \(XY^2-(XZ^2+YZ^2)=20x^2-9>0\) for positive lengths; the given lengths in fact cannot form a triangle.