2024 BTYSS P1 Q18

2024 BTYSS P1 Q18

Secondary 4
6 marks
  1. Solve \(\dfrac{2x-1}{3}=1-x\).[2]
  2. \(x^2-10x-5=(x+a)^2+b\)
    1. Find \(a\) and \(b\).[2]
    2. Hence solve \(x^2-10x-5=0\), giving your answers correct to \(2\) decimal places.[2]

Solution:

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Answer:(a) \(x=\dfrac{4}{5}\) (b)(i) \(a=-5,\ b=-30\) (ii) \(x=10.48\) or \(-0.48\)

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