2024 ASRJC Promo Q2

2024 ASRJC Promo Q2

6 marks
Promo

It is given that \(y=\tan 3x\).

  1. Show that \(\frac{{{\mathrm{d}}^{2}}y}{\mathrm{d}{{x}^{2}}}=Ay\frac{\mathrm{d}y}{\mathrm{d}x}\), where \(A\) is a constant to be determined.[3]
  2. Hence show that \(\frac{{{\mathrm{d}}^{4}}y}{\mathrm{d}{{x}^{4}}}=B\frac{\mathrm{d}y}{\mathrm{d}x}\frac{{{\mathrm{d}}^{2}}y}{\mathrm{d}{{x}^{2}}}+Cy\frac{{{\mathrm{d}}^{3}}y}{\mathrm{d}{{x}^{3}}}\), where \(B\) and \(C\) are constants to be determined.[3]

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Answer:(a) \(A=6\) (b) \(B=18\) and \(C=6\).

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