2024 ACS(BR) P2 Q8

2024 ACS(BR) P2 Q8

Secondary 4
8 marks

\(ABCD\) is a rectangle which fits inside a semicircle of radius \(8\text{ cm}\) and centre \(O\). It is given that \(AB=x\text{ cm}\) and \(BC=y\text{ cm}\).

  1. Show that \(A\text{ cm}^2\), the area of the rectangle, is given by \(A=\dfrac x2\sqrt{256-x^2}\).[2]
  2. Given that \(x\) can vary, find the value of \(x\) which gives a stationary value of \(A\).[4]
  3. By considering the sign of \(\dfrac{\mathrm{d}A}{\mathrm{d}x}\), determine whether the stationary value of \(A\) is maximum or minimum.[2]

Solution:

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Answer:(a) \(A=\dfrac x2\sqrt{256-x^2}\). (b) \(x=8\sqrt2\text{ cm}\approx11.3\text{ cm}\). (c) Maximum.

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