2024 ACS(BR) P2 Q10

2024 ACS(BR) P2 Q10

Secondary 4
10 marks

The diagram shows the side view of a \(14\text{ cm}\) by \(8\text{ cm}\) rectangular block \(PQRS\), placed on a ramp, \(VS\), tilted at an acute angle of \(\theta^\circ\).

The ramp is placed on a horizontal surface \(ST\) and \(d\) is the perpendicular distance from \(Q\) to \(ST\). \(\angle VTS=90^\circ\).

  1. Show that \(d=8\cos\theta+14\sin\theta\).[2]
  2. Express \(d\) in the form \(R\cos(\theta-\alpha)\), where \(R>0\) and \(0^\circ<\alpha<90^\circ\).[4]
  3. Find the smallest value of \(\theta\) such that \(d=10\sqrt2\).[4]

Solution:

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Answer:(a) \(d=8\cos\theta+14\sin\theta\). (b) \(2\sqrt{65}\cos(\theta-60.3^\circ)\). (c) \(31.5^\circ\).

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