Trigonometry - Applications of Trigonometric Ratios

Trigonometry - Applications of Trigonometric Ratios

IP 2
7 marks

The diagram shows a crane which has lifted a load from the ground. Loads are lifted and lowered vertically. The length of the arm of the crane is \(a\text{ metres}\) and the angle the arm makes with the horizontal is \(\theta^\circ\). The distance from the base of the cabin to the load when resting on the ground is \(x\text{ metres}\).

  1. Given that the height of the cabin is \(2.5\text{ m}\), \(x = 15\text{ m}\) and \(a = 25\text{ m}\), find the height of the highest point of the crane from the ground.

    [2]

The Safety Manual for the crane includes the following information:
The maximum load the crane can lift is \(9000\text{ kg}\).
The table below shows the percentage of the maximum load that can be lifted when the length and angle of the arm are changed.

Arm length, \(a\) (m)Angle, \(\theta\)
\(20^\circ\)\(40^\circ\)\(60^\circ\)\(80^\circ\)
\(15\)\(65\%\)\(80\%\)\(90\%\)\(100\%\)
\(20\)\(50\%\)\(65\%\)\(80\%\)\(90\%\)
\(25\)\(30\%\)\(50\%\)\(65\%\)\(80\%\)
\(30\)\(10\%\)\(30\%\)\(50\%\)\(65\%\)

Use the information from the Safety Manual to help you answer the following questions.

  1. Find the values of \(a\) and \(\theta\) for the crane to lift a load of \(9000\text{ kg}\).

    [1]
  2. A load of \(5850\text{ kg}\) is transported by the crane, and the crane is set to reach the maximum height allowed. Given that workers are not allowed to stand directly under the arm of a crane, work out the minimum distance that workers can safely stand from the cabin.

    [4]

Solution:

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Answer:(a) \(22.5\text{ m}\). (b) \(a=15\text{ m}\), \(\theta=80^\circ\). (c) Boundary distance \(x=30\cos80^\circ\approx5.21\text{ m}\); stand beyond the arm’s horizontal reach.

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