A stone was thrown from the top of a vertical cliff. The height, \(h\) metres, of the stone above sea level \(t\) seconds after it is released can be modelled by the equation \(h = 9t + 20 - 3t^2\).\nSome corresponding values of \(t\) and \(h\) are given in the table below.
| \(t\) | \(0\) | \(1\) | \(2\) | \(3\) | \(4\) | \(5\) | \(6\) |
|---|---|---|---|---|---|---|---|
| \(h\) | \(20\) | \(26\) | \(26\) | \(20\) | \(8\) | \(-10\) | \(-34\) |
State the height of the cliff.
[1]On the grid, draw the graph of \(h = 9t + 20 - 3t^2\) for \(0 \le t \le 6\).
[2]Use your graph in part (b) to estimate
the maximum height of the stone above sea level and the time at which this occurs,
[2]the length of time at which the stone is more than \(23\text{ m}\) above sea level.
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