The diagram shows a trapezium $ABCD$.\nAngle $ABD = \text{angle}\hspace{0.5em} BDC = 90^\circ$.\

Question

The diagram shows a trapezium $ABCD$.\nAngle $ABD = \text{angle}\hspace{0.5em} BDC = 90^\circ$.\n$AD = 13.5\text{ cm}$, $BC = 11.4\text{ cm}$ and angle $DAB = 42^\circ$. Calculate angle $CBD$.[4]

Accepted Answer

$\angle CBD \approx 37.6^\circ$

Basic Geometry

Basic Geometry

Solution:

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