The volume \(V\text{ cm}^3\), of liquid contained in a tank is given by \(V=\dfrac23\pi h^3\), where \(h\) cm is the depth of the liquid. If liquid is pumped into the tank at a constant rate of \(30\text{ cm}^3/\text{s}\), determine the rate of increase of \(h\) when \(h=2.5\) cm, leaving your answer in terms of \(\pi\).[4]
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