2023 VJC Promo Q3

2023 VJC Promo Q3

7 marks
Promo

Given that \(a\in \mathbb{R}\) and \(a>1\), use an algebraic method to solve the inequality

\(\frac{ax-a+2}{\left( x-a \right)\left( 1-x \right)}\le 1\).[5]

Hence find the set of values of \(x\) such that \(\frac{a\left| x \right|-a+2}{\left( \left| x \right|-a \right)\left( 1-\left| x \right| \right)}\le 1\).[2]

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Answer:(i) \(x < 1\) or \(x>a\) (ii) \(-1 < x < 1\) or \(x>a\) or \(x<-a\)

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