2023 VJC P1 Q5

The diagram below shows the graph of \(y=\mathrm{f}\left( x \right)\).

The curve has asymptotes with equations \(x=-8\) and \(y=-x+2\). It passes through the origin and \(\left( -6,0 \right)\) and has turning points at \(\left( -12,18 \right)\) and \(\left( -4,2 \right)\). On separate clearly labelled diagrams, sketch the graphs of

1. \(y=\mathrm{f}\,\mathrm{ }\!\!'\!\!\mathrm{ }\left( x \right)\),[3]
2. \(y=\frac{1}{\mathrm{f}\left( x \right)}\).[4]