2023 SCGS 4AM CA2 Q6

2023 SCGS 4AM CA2 Q6

Secondary 4
8 marks

The diagram shows a trapezium \(OPQR\), where \(OR=6\) cm and \(\angle OPQ=\angle PQR=\frac{\pi}{2}\) radians. \(\angle ROP=\theta\) radians, where \(\theta\) is acute. \(T\) is a point on \(PQ\) such that \(\angle ORT=\frac{\pi}{2}\) radians and \(RT=3\) cm.

  1. Show that the area of the trapezium \(OPQR\) is \((9\sin2\theta+18\sin^2\theta)\text{ cm}^2\).[3]
  2. Given that \(\theta\) can vary, find the exact value of \(\theta\) for which the area of trapezium \(OPQR\) is stationary.[3]
  3. Determine whether this value of \(\theta\) gives a maximum or minimum value of the area.[2]

Solution:

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Answer:(a) \(A=9\sin2\theta+18\sin^2\theta\text{ cm}^2\) (shown) (b) \(\theta=\dfrac{3\pi}{8}\) radians (c) Maximum area.

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