Given that \(y=\dfrac{x^3-2}{1+3x}\), find \(\dfrac{\mathrm dy}{\mathrm dx}\).[3]
Given that \(y=3x^2(2x+1)^4\), find \(\dfrac{\mathrm dy}{\mathrm dx}\), giving your answer in the form \((2x+1)^3\mathrm f(x)\) where \(\mathrm f(x)\) is a quadratic expression.[4]
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