The volume, \(V\text{ cm}^3\), of water in a tank may be modelled by the equation \(V=\dfrac13\pi x^3\), where \(x\) cm is the depth of the water in the tank. When the tap is turned on, the volume of water in the tank increases at a rate of \(0.2\text{ cm}^3/\text{min}\). Find the rate at which the depth of water in the tank is increasing when \(x=0.9\).[5]
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