In the diagram below, \(TAX\) and \(TCY\) are tangents to the circle at \(A\) and \(C\) respectively. \(AC\) meets \(TD\) at \(E\) and \(D\) is on \(BC\) such that \(TD\) is parallel to \(AB\).
Prove that \(CE \times EA = DE \times TE\).
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