The volume, \(V\text{ cm}^3\), of water in a container is given by \(V=\dfrac{4x^3}3-2x+3\), where \(x\) cm is the depth of water in the container. Given that water is being poured into the container at a constant rate of \(52\text{ cm}^3/\text{s}\), find the rate at which the depth of water is increasing when \(x=5\) cm.[4]
Sign in to view the step-by-step solution
Need help? Join our JC Math tuition classes.
Learn more