Without using a calculator, solve the inequality $\frac{x}{2x-1}\le \frac{1}{3x+2}$. [3] Hence find

Question

Without using a calculator, solve the inequality $\frac{x}{2x-1}\le \frac{1}{3x+2}$. [3] Hence find the exact values of $x$ for which $\frac{{{x}^{2}}}{2{{x}^{2}}-1}\le \frac{1}{3{{x}^{2}}+2}$. [2]

Accepted Answer

$-\dfrac23<x<\dfrac12$ Hence: $-\dfrac1{\sqrt2}<x<\dfrac1{\sqrt2}$

2023 JPJC Promo Q2

2023 JPJC Promo Q2

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