If $ x^2 + y^2 = 20 $ and $ xy = 6 $, find the value of $ (x-y)^2 $. [2] The difference of two

Question

If $ x^2 + y^2 = 20 $ and $ xy = 6 $, find the value of $ (x-y)^2 $. [2] The difference of two numbers $ \dfrac{2}{x+1} $ and $ \dfrac{2}{x} $ is $ 1 $, where $ x $ is a negative integer. Form an equation in terms of $ x $ and show that it reduces to $ x^2 + x - 2 = 0 $. [3] Hence, find the value of $ x $. [2]

Accepted Answer

(a) $8$ (b)(i)$x^2+x-2=0$ (b)(ii)$x=-2$

Quadratic Functions, Equations and Inequalities - Evaluating Expressions using Special Identities

Quadratic Functions, Equations and Inequalities - Evaluating Expressions using Special Identities

Solution:

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