2023 DHS Promo Q2

2023 DHS Promo Q2

4 marks

Promo

Given that \(x<0\), solve the inequality \(\frac{2}{x}<\left| x \right|-a\), where \(a\) is constant such that \(a>3\).[4]

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Answer:\(x<\dfrac{-a-\sqrt{a^2-8}}2\) or \(\dfrac{-a+\sqrt{a^2-8}}2<x<0\)

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