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2023 CSS AM S3 EOY Q9

2023 CSS AM S3 EOY Q9

Secondary 3
9 marks
  1. Solve the equation \(\log_2 (x + 3) - \log_4 (3x + 1) = 1\).[4]
  2. It is given that \(\ln p - \ln(p + q) = \ln q\).
    1. Express \(p\) in terms of \(q\).[3]
    2. State the range of values of \(p\) and explain clearly why \(0 < q < 1\).[2]

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Answer:(a) \(x=1\) or \(x=5\) (b)(i) \(p=\dfrac{q^2}{1-q}\) (ii) \(p>0\) and \(0<q<1\)

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