Triangle \(ABC\) is congruent to triangle \(DAE\).
\(ACE\) is a straight line.
Given that \(AD = 8.7\text{ cm}\), \(CE = 2.2\text{ cm}\), \(DE = 6.8\text{ cm}\), angle \(ADE = 70^\circ\) and angle \(ACB = 65^\circ\).
Tom states that \(AB\) is parallel to \(DE\).
Show, with calculations, whether you agree with Tom.
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