Express ${\mathrm{f}(x) = 3x^2 - 12x + 1}$ in the form ${a(x - b)^2 + c}$ where ${a}$, ${b}$, and ${

Question

Express ${\mathrm{f}(x) = 3x^2 - 12x + 1}$ in the form ${a(x - b)^2 + c}$ where ${a}$, ${b}$, and ${c}$ are constants. [2] Hence explain why the minimum point of ${\mathrm{f}(x)}$ occurs when ${y = -11}$. [2]

Accepted Answer

(a) $f(x)=3(x-2)^2-11$, where $a=3$, $b=2$, and $c=-11$ (b) Minimum value $-11$ at $x=2$

2023 BSS 3AM EOY Q1

2023 BSS 3AM EOY Q1

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