2023 ACSBR AM S3 EOY Q11
2023 ACSBR AM S3 EOY Q11
Secondary 3
8 marks
The diagram shows an L-shaped rod \(ABC\) leaning against a vertical wall.
\(AB=8\) cm, \(BC=15\) cm and angle \(\angle BCO=\theta\).
L-shaped rod ABC leaning against a wall
- Show that \(OC = 8 \sin \theta + 15 \cos \theta\).[2]
- Express \(OC\) in the form \(R \sin(\theta + \alpha)\), where \(R > 0\) and \(0{}^\circ < \alpha < 90{}^\circ\).[4]
- Find the values of \(\theta\) when \(OC=16\) cm.[2]
Video Solution:
Video solution locked
Solution:
Solution locked
Sign in to view the step-by-step solution
Finding similar questions...
Answer:(a) \(OC=8\sin\theta+15\cos\theta\) (b) \(OC=17\sin(\theta+61.9{}^\circ)\) (c) \(\theta=8.3{}^\circ\) or \(47.8{}^\circ\)
Need help? Join our JC Math tuition classes.
Learn more