2023 ACJC Promo Q6

2023 ACJC Promo Q6

9 marks
Promo

Referred to the origin \(O\), the points \(P\) and \(Q\) have position vectors \(\mathbf{p}\) and \(\mathbf{q}\) respectively, where vector \(\mathbf{p}\) and \(\mathbf{q}\) are not parallel. Point \(A\) lies between \(P\) and \(Q\), such that \(PA:AQ=\lambda :\left( 1-\lambda \right)\), where \(0<\lambda <1\).

  1. Express \(\overrightarrow{OA}\) in terms of \(\mathbf{p}\), \(\mathbf{q}\) and \(\lambda \).[1]
  2. The point \(B\) lies between \(O\) and \(Q\), such that \(OB:OQ=1:3\). Given that \(\overrightarrow{AB}\) is parallel to \(\left( \mathbf{q}-4\mathbf{p} \right)\), find the value of \(\lambda \).[4]
  3. It is now given that \(\mathbf{p}\) is a unit vector which is perpendicular to \(\mathbf{q}\) and \(\left| \mathbf{q} \right|=2\), find the area of triangle \(OAQ\), in terms of \(\lambda \).[4]

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Answer:(i) \(\overrightarrow{OA}=(1-\lambda)\mathbf p+\lambda\mathbf q\) (ii) \(\lambda=\dfrac19\) (iii) area of \(\triangle OAQ=1-\lambda\text{ units}^2\)

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