2022 VJC J1 MYE Q4

2022 VJC J1 MYE Q4

7 marks
Mid Year Exam

It is given that \(a\) is a constant and \(0 < a < 1\).

  1. Solve algebraically the equation \(\left| x\left( x-1 \right) \right|=ax\).[3]
  2. On the same axes, sketch the curves with equations \(y=\left| x\left( x-1 \right) \right|\) and \(y=ax\).
    Hence solve the inequality \(\left| x\left( x-1 \right) \right|\le ax\).[4]

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs a course plan.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Answer:(i) x = 0, 1-a, 1+a; (ii) x = 0 or 1-a ≤ x ≤ 1+a

Need help? Join our JC Math tuition classes.

Learn more