2022 TMJC J1 MYE Q8

2022 TMJC J1 MYE Q8

14 marks
Mid Year Exam

Relative to the origin \(O\), the position vectors of the points \(A\), \(B\) and \(C\) are \(4\mathbf{i}+\mathbf{j}+3\mathbf{k}\), \(-6\mathbf{i}+3\mathbf{j}-7\mathbf{k}\) and \(-2\mathbf{i}+7\mathbf{j}-6\mathbf{k}\) respectively. The plane \(p\) contains the points \(A\) and \(C\). \(p\) is also parallel to the vector \(\left( \begin{matrix} -3 \\ 6 \\ 2 \\ \end{matrix} \right)\).

  1. Show that the cartesian equation of \(p\) can be expressed as \(2x-y+6z=25\).[4]
  2. Find the coordinates of the foot of the perpendicular from \(B\) to \(p\).[4]
  3. Hence, or otherwise, find the coordinates of the point of reflection of \(B\) about \(p\).[2]
  4. The point \(M\) lies on \(AB\) extended such that \(AB:AM=3:5\). Find \(\overrightarrow{AB}\) and determine the exact shortest distance between \(M\) and \(p\).[4]

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs tuition enrolment.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.

Create a free account to practise similar questions.

Answer:(i) \(2x - y + 6z = 25\); (ii) \((-2, 1, 5)\); (iii) \((2, -1, 17)\); (iv) \(\frac{10\sqrt{41}}{3}\) units

Need help? Join our JC Math tuition classes.

Learn more