On the same axes, sketch the graphs of \(y=\frac{x-b}{x}\) and \(y=\frac{1}{a}\left| x-b \right|\), where \(0<a<1\) and \(b>1\). State the equations of any asymptotes and the coordinates of the points where the curves cross the axes.[3]
Hence solve the inequality \(\frac{x-b}{x}\le \frac{1}{a}\left| x-b \right|\).[3]
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Answer:(i) For \(y=\frac{x-b}{x}\): asymptotes \(x=0\), \(y=1\), intercept \((b,0)\). For \(y=\frac1a|x-b|\): intercepts \((b,0)\), \((0,\frac ba)\). (ii) \(x\le-a\) or \(x>0\).