In the diagram above, $AC=10$, $AD=8$, $BC=5$, angle $ADC$ is a right angle and angle $BCD= heta $

Question

In the diagram above, $AC=10$, $AD=8$, $BC=5$, angle $ADC$ is a right angle and angle $BCD=	heta $ radians. By considering angle $ACD$, show that $AB\approx {{\left( 65-80	heta +30{{	heta }^{2}} ight)}^{\frac{1}{2}}}\approx p+q	heta +r{{	heta }^{2}}$ is a sufficiently small angle, where $p$, $q$ and $r$ are constants to be determined exactly. [7]

Accepted Answer

$p=\sqrt{65}$, $q=-\frac8{13}\sqrt{65}$, $r=\frac7{169}\sqrt{65}$

2022 NJC J2 CT P1 Q2

2022 NJC J2 CT P1 Q2

Video Solution:

Solution:

Solution locked