2022 HCI Promo Q2

2022 HCI Promo Q2

6 marks
Promo

The equation of a curve \(G\) is given by

\({{x}^{2}}y-\ln y=1\), where \(x<0\) and \(y>0\).

  1. Show that \(\frac{\mathrm{d}y}{\mathrm{d}x}=\frac{2x{{y}^{2}}}{1-{{x}^{2}}y}\).[3]
  2. Find the equation of the tangent to \(G\) at the point \(P\) where \(y=1\).[3]

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs tuition enrolment.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.

Create a free account to practise similar questions.

Answer:(a) shown; (b) \(x = -1\)

Need help? Join our JC Math tuition classes.

Learn more