Sketch, on the same axes, the graphs of $y=\frac{x}{x+a}$ and $y=1-\left| x+a \right|$, where $a$ is

Question

Sketch, on the same axes, the graphs of $y=\frac{x}{x+a}$ and $y=1-\left| x+a \right|$, where $a$ is a constant such that $a>1$. [3] Hence, solve the inequality $\frac{x}{x+a}>1-\left| x+a \right|$. [3]

Accepted Answer

(i) Sketch shown (ii) $\{x \in \mathbb{R}: x -a + \sqrt{a}\}$

2022 EJC J1 MYE Q2

2022 EJC J1 MYE Q2

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