Emma has a computer program that generates a random positive integer \(X\). The probability distribution of \(X\) is:
\(\mathrm{P}\left( X=r \right)=\frac{a}{{{r}^{3}}}\), \(r\in {{\mathbb{Z}}^{+}}\) and \(a\) is positive constant.
For the rest of the question, you may use the following results:
\(\sum\limits_{m=1}^{\infty }{\frac{1}{m}}\) does not exist, \(\sum\limits_{m=1}^{\infty }{\frac{1}{{{m}^{2}}}=\mathrm{1}\mathrm{.6449}}\) and \(\sum\limits_{m=1}^{\infty }{\frac{1}{{{m}^{3}}}=\mathrm{1}\mathrm{.2021}}\).
Emma generates \(10\) numbers using her program namely, \({{X}_{1}}\), \({{X}_{2}}\), ... ,\({{X}_{10}}\). The random variable \(Y\) denotes the number of times the number ‘\(3\)’ occurs among the \(10\) numbers. You can assume that the numbers generated by the program are independent of each other.
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