2022 BTYSS P1 Q9

2022 BTYSS P1 Q9

Secondary 4
8 marks

The equation of a curve is \(y=\dfrac{\sqrt{2x^2+1}}{x-3}\).

  1. Find \(\dfrac{\mathrm dy}{\mathrm dx}\).[4]
  2. Find the equation of the tangent to the curve at \(x=2\).[4]

Solution:

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Answer:(a) \(\dfrac{-6x-1}{(x-3)^2\sqrt{2x^2+1}}\). (b) \(y=-\dfrac{13}3x+\dfrac{17}3\).

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