2022 ACJC P1 Q5

2022 ACJC P1 Q5

7 marks
Prelims

Do not use a calculator in answering this question.

Two complex numbers are \({{z}_{1}}=2\left( \cos \frac{\pi }{18}-\mathbf{i}\sin \frac{\pi }{18} \right)\) and \({{z}_{2}}=2\mathbf{i}\).

  1. Show that \(\frac{{{z}_{1}}^{2}}{{{z}_{1}}^{*}}+{{z}_{2}}\) is \(\sqrt{3}+\mathbf{i}\).[3]
  2. A third complex number, \({{z}_{3}}\), is such that \(\left( \frac{{{z}_{1}}^{2}}{{{z}_{1}}^{*}}+{{z}_{2}} \right){{z}_{3}}\) is real and \(\left| \left( \frac{{{z}_{1}}^{2}}{{{z}_{1}}^{*}}+{{z}_{2}} \right){{z}_{3}} \right|=\frac{2}{3}\). Find the possible values of \({{z}_{3}}\) in the form of \(r(\cos \theta +\mathbf{i}\sin \theta )\), where \(r>0\) and \(-\pi <\theta \le \pi \).[4]

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Answer:(ii) \({\frac{1}{3}\left( \cos \left( -\frac{\pi }{6} \right)+\mathbf{i}\sin \left( -\frac{\pi }{6} \right) \right)}\) \text{ or } \({\frac{1}{3}\left( \cos \frac{5\pi }{6}+\mathbf{i}\sin \frac{5\pi }{6} \right)}\)

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