Compound Interest with regular writhdrawals

Compound Interest with regular writhdrawals

A fund is started at \(\$1000\) and compound interest is reckoned at \(4\%\) per annum.

If withdrawals of \(\$50\) are made at the beginning of each of the subsequent years, show that the amount in the fund at the beginning of the \({(n+1)^{\mathrm{th}}}\) year is \(\$\) \(1250\left[1 - \frac{1}{5}(1.04)^n\right]\)

Find the amount in the fund to the nearest dollar after twenty years, and also how many years it will last.

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Answer:Fund at the beginning of year \(n+1\): \(1250\left[1-\frac15(1.04)^n\right]\). After \(20\) years: \(\$702\). Duration: \(42\) years.

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