For events \(A\),\(B\) and \(C\) it is given that \(\mathrm{P}\left( A \right)=0.8\), \(\mathrm{P}\left( B \right)=0.4\), \(\mathrm{P}\left( C \right)=c\) and \(\mathrm{P}\left( A\cup B \right)=0.95\).
It is now given that \(\mathrm{P}\left( C \right)=\mathrm{P}\left( \left. C \right|A \right)=0.45\).
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