2021 SJI P1 Q7

2021 SJI P1 Q7

IB Year 5 | Grade 11
18 marks

The diagram shows the graph of the function \(y=\mathrm{f}(x)\) where

\[\mathrm{f}(x)=\frac{ax+b}{x^2+cx+d}\]

with \(\mathrm{f}\left(-\dfrac52\right)=0,\ \mathrm{f}(0)=\dfrac54\). The lines \(x=-4,\ x=-1\) and the \(x\)-axis are all asymptotes.

  1. Using the information given, find the value of \(c\) and of \(d\) and show that \(a=2,\ b=5\).[4]
  2. Using the values of \(a,\ b,\ c,\) and \(d\) found in (a), find the value of \(A\) and of \(B\) for which \(\mathrm{f}(x)=\dfrac A{x+4}+\dfrac B{x+1}\).[3]
  3. Show that \(\left(-\dfrac52,0\right)\) is a point of inflexion.[3]
  4. State the set of values of \(x\) for which \(\mathrm{f}'(x)<0\).[2]
  5. State the set of values of \(x\) for which \(\mathrm{f}''(x)>0\).[2]
  6. Sketch the graph of \(y=\mathrm{f}'(x)\), clearly indicating any intercepts with the axes, the coordinates of any local maximum or minimum points and the equations of the asymptotes (if any).[4]

Solution:

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Answer:(a) \(c=5,d=4,a=2,b=5\) (b) \(A=B=1\) (c) Shown (d) \(\mathbb R\setminus\{-4,-1\}\) (e) \(-4<x<-\dfrac52\) or \(x>-1\) (f) Maximum \(\left(-\dfrac52,-\dfrac89\right)\); \(y\)-intercept \(-\dfrac{17}{16}\); asymptotes \(x=-4,-1\) and \(y=0\).

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