<ol class="i-list"><li><div class="list-item-content"><span class="list-item-text">On the same axes, sketch the curves with equations, $y=\left| \frac{ax-3a+2}{3-x} \right|$ and $y=\frac{a}{3}x$, where $a>1$, giving the equations of the asymptotes and the coordinates of the points where the curves meet the axes.</span></div><p style="text-align: right;">[3]</p></li><li><div class="list-item-content"><span class="list-item-text">Hence, solve the inequality $\left| \frac{ax-3a+2}{3-x} \right|>\frac{a}{3}x$, giving your answer in terms of $a$.</span></div><p style="text-align: right;">[3]</p></li></ol>

On the same axes, sketch the curves with equations, $y=\left| \frac{ax-3a+2}{3-x} \right|$ and $y=\frac{a}{3}x$, where $a>1$, giving the equations of the asymptotes and the coordinates of the points where the curves meet the axes.

Hence, solve the inequality $\left| \frac{ax-3a+2}{3-x} \right|>\frac{a}{3}x$, giving your answer in terms of $a$.

2021 NYJC P1 Q2

2021 NYJC P1 Q2

Video Solution:

Solution:

Handwritten Solution