2021 NJC Promo Q5

2021 NJC Promo Q5

7 marks
Promo

It is given that

\(\mathrm{f}\left( x \right)=\left\{ \begin{matrix} {{\left( x-2 \right)}^{2}},0\le x<2 \\ 2x-4,2\le x\le 4 \\ \end{matrix} \right.\)

and that \(\mathrm{f}\left( x \right)=\mathrm{f}\left( x+4 \right)\) for all real values of \(x\).

  1. State the value of \(\mathrm{f}\left( 21 \right)\).[1]
  2. Sketch the graph of \(y=\mathrm{f}\left( x \right)\) for \(-6\le x\le 6\).[2]

The function \(\mathrm{g}\) is defined by

\(\mathrm{g}\left( x \right)=\sqrt{x-4}\), \(4\le x\le 20\).

  1. Find \(\mathrm{fg}\) in a similar form as \(\mathrm{f}\).[4]

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs tuition enrolment.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.

Create a free account to practise similar questions.

Answer:(i) 1 (iii) \(fg(x) = \begin{cases} (\sqrt{x-4}-2)^2, & 4 \leq x < 8 \\ 2\sqrt{x-4}-4, & 8 \leq x \leq 20 \end{cases}\)

Need help? Join our JC Math tuition classes.

Learn more